Suppose p∈P(R)p \in \mathcal P(\mathbf R). Prove that there exists a polynomial q∈P(R)q \in \mathcal P(\mathbf R) such that 5q′′+3q′=p5q'' + 3q' = p.


Define Dp=5p′′+3p′Dp = 5p'' + 3p' and notice deg⁡Dp=(deg⁡p)−1\deg Dp = (\deg p) - 1, then apply 3b/26